Mar 20, 2012 · If SQL server compatibility allows that, then this is the best answer. E.g. Select Count (value)-1 From STRING_SPLIT ('Hello World','l') counts the number of letter "l" in the Text.

Jul 8, 2012 · If I understand correctly you are using Oracle PLSQL, and as far as I know, there isn't any "built-in" method (in PLSQL) that counts the number of digits/characters in a string. But, you can do the following to count characters: select LENGTH(REGEXP_REPLACE('abcd12345','[0-9]')) from dual and digits:

Dec 28, 2020 · How can I check if a string consists of letters or numbers ONLY in Transact-SQL? Here the string has datatype nchar, 'letters' specifically refer to latin characters.

Apr 16, 2024 · In the world of SQL, the LENGTH () function provides an essential tool for measuring the number of characters in a string, which can be invaluable for various tasks such as data validation, formatting, and manipulation.

Nov 11, 2021 · We can do it this way: SELECT LEN(summary) - LEN(REPLACE(summary, 'x', '')) AS occurrences FROM article Here’s what this expression does: Gets the number of characters in the superstring; Deletes the x’s from the superstring and counts the characters again; Returns the difference or, in other words, the number of x’s.

Dec 20, 2023 · This SQL Server tutorial will teach you about SQL Server count characters in string. You will learn about the two methods, LEN () and DATELENGTH (), to count the number of characters in the given string.

In this blog you will learn how to count the number of occurrences of a character or word in a string in SQL Server .

Jun 5, 2020 · In today's blog, we'll learn how to count the number of string occurrences within a char, varchar or text field using a couple of native SQL string functions. The two functions that we'll be using here today are LENGTH (str) and REPLACE (str, from_str, to_str).

Aug 16, 2010 · How many times the character/word exists in string? How many total characters exists in Occurrence? Let us see following example and it will clearly explain it to you. DECLARE @LongSentence VARCHAR(MAX) DECLARE @FindSubString VARCHAR(MAX) SET @LongSentence = 'My Super Long String With Long Words' SET @FindSubString = 'long'

Apr 20, 2017 · Try this: SELECT COUNT(DECODE(SUBSTR(UPPER(:main_string),rownum,LENGTH(:search_char)),UPPER(:search_char),1)) search_char_count FROM DUAL connect by rownum <= length(:main_string); It determines the number of single character occurrences as well as the sub-string occurrences in main string.